Physics for Scientists and Engineers 3E by R. Knight, P1.23

Solution:

$\displaystyle 6.15\:ms$

$\displaystyle =\left(6.15\:ms\right)\left(\frac{1\:s}{10^3\:ms}\right)$

$\displaystyle =6.15\times 10^{-3}\:s$ ☚

$\displaystyle 27.2\:km$

$\displaystyle =\left(27.2\:km\right)\left(\frac{10^3\:m}{1\:km}\right)$

$\displaystyle =27.2\times 10^3\:m$ ☚

$\displaystyle 112\:km/hour$

$\displaystyle =\left(112\:\frac{km}{hour}\right)\left(\frac{10^3\:m}{1\:km}\right)\left(\frac{1\:hour}{3600\:s}\right)$

$\displaystyle =31.1\:m/s$ ☚

$\displaystyle 72\:\mu m/ms$

$\displaystyle =\left(72\:\frac{\mu m}{ms}\right)\left(\frac{1\:m}{10^6\:\mu m}\right)\left(\frac{10^3\:ms}{1\:s}\right)$

$\displaystyle =7.2\times 10^{-2}\:m/s$ ☚