# College Physics Problem 2.4

## Solution:

### Part a

The position of D started from 9 m, then went to 3 m, and then went back to 5 m. The distance traveled by D is the sum of all the paths

$\displaystyle \text{distance}=6\:\text{m}+2\:\text{m}=8\:\text{m}$          ☚

### Part b

The magnitude of the displacement is the difference between the final position and the initial position WITHOUT regards to sign

$\displaystyle \left|\Delta x\right|=\left|9\:\text{m}-5\:\text{m}\right|=4\:\text{m}$          ☚

### Part c

The displacement is difference between the final position and the initial position TAKING INTO ACCOUNT the sign

$\displaystyle \:\Delta x=5\:\text{m}-9\:\text{m}=-4\:\text{m}$          ☚