# College Physics Problem 2.16

#### A cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration?

SOLUTION:

The formula for acceleration is

$a=\frac{change\:in\:velocity}{time}=\frac{\Delta v}{time}=\frac{v_f-v_0}{t}$

Substituting the given values

$a=\frac{30.0\:\frac{m}{s}-0}{7.00\:s}$

$a=4.29\:m/s^{2}$

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