College Physics Problem 2.22

A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 6.20\times\:10^{5}m/s^2 for 8.10\times\:10^{-4}\:s  . What is its muzzle velocity (that is, its final velocity)?

Solution:

v=v_o+at
v=0\:m/s\:+\:\left(6.20\times 10^5\:m/s^2\right)\left(8.10\times 10^{-4}\:s\right)
v=502\:m/s

Therefore, the muzzle velocity, or final velocity, is 502 m/s. 

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