# College Physics 2.22 – Muzzle velocity of a bullet

## Solution:

The muzzle velocity of the bullet is computed as follows:

$\displaystyle \text{v}=\text{v}_0+\text{at}$

$\displaystyle \text{v}=0\:\text{m/s}+\left(6.20\times 10^5\text{ m/s}^2\right)\left(8.10\times 10^{-4}\:\text{s}\right)$

$\displaystyle \text{v}=502\:\text{m/s}$

Therefore, the muzzle velocity, or final velocity, is 502 m/s.