# College Physics Problem 2.22

#### A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of $6.20\times\:10^{5}m/s^2$ for $8.10\times\:10^{-4}\:s$  . What is its muzzle velocity (that is, its final velocity)?

Solution:

$v=v_o+at$
$v=0\:m/s\:+\:\left(6.20\times 10^5\:m/s^2\right)\left(8.10\times 10^{-4}\:s\right)$
$v=502\:m/s$

Therefore, the muzzle velocity, or final velocity, is 502 m/s.

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