College Physics 2.26 – Blood acceleration

Blood is accelerated from rest to 30.0 cm/s in a distance of 1.80 cm by the left ventricle of the heart.

(a) Make a sketch of the solution.

(b) List the knowns in this problem.

(c) How long does the acceleration take? To solve this part, first identify the unknown, and then discuss how you chose the appropriate equation to solve for it. After choosing the equation, show your steps in solving for the unknown, checking your units.

(d) Is the answer reasonable when compared with the time for a heartbeat?


Part A

The sketch should contain the starting point and the final point. This will be done by connecting a straight line from the starting point to the final point. The sketch is shown below.

College Physics Problem 2.26

Part B

The list of known variables are:

Initial velocity: \text{v}_0=0\:\text{m/s}
Final Velocity: \text{v}=30.0\:\text{cm/s}
Distance Traveled: \text{x}-\text{x}_0=1.80\:\text{cm}

Part C

The best equation to solve for this is \:\:\Delta \text{x}=\text{v}_{\text{ave}}\text{t} where \text{v}_{\text{ave}} is the average velocity, and t is time. That is

\Delta \text{x}=\text{v}_{\text{ave}}\text{t}

\displaystyle \:\text{t}=\frac{\Delta \text{x}}{\text{v}_{\text{ave}}}

\displaystyle \:\text{t}=\frac{1.80\:\text{cm}}{\frac{\left(0\:\text{cm/s}+30\:\text{cm/s}\right)}{2}}


Part D

Since the computed value of the time for acceleration of blood out of the ventricle is only 0.12 seconds (only a fraction of a second), the answer seems reasonable. This is due to the fact that an entire heartbeat cycle takes about one second. So, the answer is yes, the answer is reasonable.