Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 3

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PROBLEM:

If y=tan⁡(x+π) \displaystyle y= \tan\left(x+\pi \right), find xx as a function of yy.

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SOLUTION:

y=tan⁡(x+π)x+π=tan⁡−1yx=tan⁡−1y−π  (Answer)\begin{align*} y & = \tan\left(x+\pi \right) \\ x+\pi & = \tan^{-1}y \\ x & = \tan^{-1}y-\pi \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)\\ \end{align*}
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