Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 3


If y=tan\left(x+\pi \right), find x as a function of y.


Solution:

\displaystyle y=tan\left(x+\pi \right)

\displaystyle x+\pi =tan^{-1}y

\displaystyle x=tan^{-1}y-\pi


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