# Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 3

#### If $y=tan\left(x+\pi \right)$, find x as a function of y.

SOLUTION:

$y=tan\left(x+\pi \right)$

$x+\pi =tan^{-1}y$

$x=tan^{-1}y-\pi$