# Differential and Integral Calculus by Feliciano and Uy: Limit of a Function, Exercise 1.2, Problem 1

#### Evaluate $\lim\limits _{x\to 2}\left(x^2-4x+3\right)$.

SOLUTION:

$\lim\limits_{x\to 2}\left(x^2-4x+3\right)=\lim \limits_{x\to 2}\left(x^2\right)-\lim\limits_{x\to 2}\left(4x\right)+\lim\limits_{x\to 2}\left(3\right)$

$=\left[\lim\limits _{x\to 2}\left(x\right)\right]^2-4\lim\limits _{x\to 2}\left(x\right)+3$

$=\left(2\right)^2-4\left(2\right)+3$

$=-1$

Do you need help in your homework? You can contact us by clicking on the Help button above, or you may click here.

Advertisements