Differential and Integral Calculus| Feliciano and Uy| Limit of a Function| Exercise 1.2| Problem 1


Evaluate \displaystyle \lim _{x\to 2}\left(x^2-4x+3\right).


Solution:

\displaystyle \lim_{x\to 2}\left(x^2-4x+3\right) =\lim_{x\to 2}\left(x^2\right)-\lim_{x\to 2}\left(4x\right)+\lim_{x\to 2}\left(3\right)

\displaystyle =\left[\lim_{x\to 2}\left(x\right)\right]^2-4\lim_{x\to 2}\left(x\right)+3

\displaystyle =\left(2\right)^2-4\left(2\right)+3

\displaystyle =-1


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