Differential and Integral Calculus| Feliciano and Uy| Limit of a Function| Exercise 1.2| Problem 7

EvaluateĀ \lim\limits_{x\to 3}\left(\frac{\sqrt{3x}}{x\sqrt{x+1}}\right).

SOLUTION:

Plug in the value x=3.

\lim\limits_{x\to 3}\left(\frac{\sqrt{3x}}{x\sqrt{x+1}}\right)=\frac{\sqrt{3\left(3\right)}}{3\sqrt{3+1}}

=\frac{\sqrt{9}}{3\sqrt{4}}

=\frac{3}{3\cdot 2}

=\frac{3}{6}

=\frac{1}{2}