College Physics by Openstax Chapter 5 Problem 1

A physics major is cooking breakfast when he notices that the frictional force between his steel spatula and his Teflon frying pan is only 0.200 N. Knowing the coefficient of kinetic friction between the two materials, he quickly calculates the normal force. What is it?

Solution:

The formula for friction is

f=μk Nf=\mu _{k\:}N

When we solve for the normal force, NN, in terms of the other variables, we have

N=fμkN=\frac{f}{\mu _k}

The coefficient of kinetic friction is 0.04. Therefore, the normal force is

N=fμkN=0.200 newton0.04N=5.00 newton  (Answer)\begin{align*} N & =\frac{f}{\mu _k} \\ N & =\frac{0.200\:\text{newton}}{0.04} \\ N & =5.00\:\text{newton} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right) \end{align*}
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