College Physics by Openstax Chapter 4 Problem 1

A 63.0-kg sprinter starts a race with an acceleration of 4.20 m/s2. What is the net external force on him?

Solution:

So, we are given mass, m=63.0 kg m = 63.0 \ \text{kg} , and acceleration, a=4.20 m/s2a = 4.20 \ \text{m/s}^2.

The net force has a formula 

F=ma\text{F}=\text{m}a

Substituting the given values, we have

F=(63.0 kg)(4.20 m/s2)F=265 kg⋅m/s2F=265 N  (Answer)\begin{align*} F & = \left( 63.0 \ \text{kg} \right)\left( 4.20 \ \text{m/s}^2 \right) \\ F & = 265 \ \text{kg}\cdot \text{m/s}^2 \\ F & = 265 \ \text{N} \ \qquad \ {\color{DarkOrange} \left( \text{Answer} \right)} \end{align*}
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