Determine the resultant internal normal and shear force in the member at (a) section a–a and (b) section b–b, each of which passes through point A. The 500-lb load is applied along the centroidal axis of the member.
SOLUTION:
Part a
The free-body diagram of section a-a is shown below.
Solve for normal force at a-a (Na) by summing forces in the normal direction
Solve for the shear force at a-a (Va) by summing forces in the shear direction
Part b
The free-body diagram of section b-b is shown below.
Solve for normal force at b-b (Nb) by summing forces in the normal direction
Solve for the shear force at b-b(Vb) by summing forces in the shear direction