Problem 1-2|Stress | Mechanics of Materials| Ninth Edition| R.C. Hibbeler|

Problem 1-2

SOLUTION:

Part a

The free-body diagram of section a-a is shown below.

Solve for normal force at a-a (Na) by summing forces in the normal direction

$\sum F_x=0$

$N_a-500=0$

$N_a=500\:lb$

Solve for the shear force at a-a (Va) by summing forces in the shear direction

$\sum F_y=0$

$V_a=0$

Part b

The free-body diagram of section b-b is shown below.

1-2b

Solve for normal force at b-b (Nb) by summing forces in the normal direction

$\sum F_x=0$

$N_b-500cos(30)=0$

$N_b=433\:lb$

Solve for the shear force at b-b(Vb) by summing forces in the shear direction

$\sum F_y=0$

$V_b-500sin(30)=0$

$V_b=250\:lb$

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