A ship has a top speed of 3 m/s in calm water. The current of the ocean tends to push the boat at 2 m/s on a bearing of due South. What will be the net velocity of the ship if the captain points his ship on a bearing of 55° North of West and applies full power?
The x component of the resultant is negative and the y component is positive, thus the resultant is located at the second quadrant.
Therefore, the magnitude of the net velocity of the ship is 1.78 m/s, and is going 14.9 degrees North of West