# Position, Velocity, and Acceleration values from Position Function| University Physics

### PART A.

Evaluate the position at time t= 3.00 s.

$x=2.00\left(3\right)^3-5.00\left(3\right)+3=42.0\:m$

### PART B.

Determine the velocity function v(t) from the position function x(t) by differentiation.

$v\left(t\right)=6t^2-5$

$v\left(t\right)=6\left(3\right)^2-5=49.0\:m/s$

### PART C.

$a\left(t\right)=12t$
$a\left(t\right)=12t=12\left(3\right)=36\:m/s^2$