Calculating Velocity from a Position-Time Graph| University Physics

Problem:

The figure is the position-versus-time graph of a jogger.

PART A. What is the jogger’s velocity at t = 10 s?

ANSWER: 1.3 m/s

The slope of the line from 0 to 20 is the constant velocity

v=\frac{50-25}{20-0}=\frac{25}{20}=1.3\:m/s

PART B. What is the jogger’s velocity at t = 25 s?

ANSWER: 0 m/s

The line is horizontal at this instant.

PART C. What is the jogger’s velocity at t = 35 s?

ANSWER: -5.0 m/s

v=\frac{0-50}{40-30}=\frac{-50}{10}=-5\:m/s

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