# Calculating Velocity from a Position-Time Graph| University Physics

### PART A. What is the jogger’s velocity at t = 10 s?

The slope of the line from 0 to 20 is the constant velocity

$v=\frac{50-25}{20-0}=\frac{25}{20}=1.3\:m/s$

### PART B. What is the jogger’s velocity at t = 25 s?

$v=\frac{0-50}{40-30}=\frac{-50}{10}=-5\:m/s$