Calculating Velocity from a Position-Time Graph| University Physics


The figure is the position-versus-time graph of a jogger.

A. What is the jogger’s velocity at t = 10 s?

B. What is the jogger’s velocity at t = 25 s?

C. What is the jogger’s velocity at t = 35 s?


Solution:

Part A

The slope of the line from 0 to 20 is the constant velocity

\displaystyle v=\frac{50-25}{20-0}=\frac{25}{20}=1.3\:m/s

Part B

The line is horizontal at this instant.

\displaystyle v=0

Part C

\displaystyle v=\frac{0-50}{40-30}=\frac{-50}{10}=-5\:m/s