Physics for Scientists and Engineers 3E by R. Knight, P1.24

Convert the following to SI units:

a) 8.0 in

b) 66 ft/s

c) 60 mph

d) 14 in2

Solution:

Part a

\displaystyle 8.0\:inch

\displaystyle =\left(8.0\:inch\right)\left(\frac{2.54\:cm}{1\:inch}\right)\left(\frac{10^{-2}\:m}{1\:cm}\right)

\displaystyle =0.20\:m          ☚

Part b

\displaystyle 66\:feet/s

\displaystyle =\left(66\:\frac{feet}{s}\right)\left(\frac{12\:inch}{1\:foot}\right)\left(\frac{1\:m}{39.37\:inch}\right)

\displaystyle =20\:m/s          ☚

Part c

\displaystyle 60\:mph

\displaystyle =\left(60\:\frac{miles}{hour}\right)\left(\frac{1.609\:km}{1\:mile}\right)\left(\frac{10^3\:m}{1\:km}\right)\left(\frac{1\:hour}{3600\:s}\right)

\displaystyle =27\:m/s          ☚

Part d

\displaystyle 14\:in^2

\displaystyle =\left(14\:inch^2\right)\left(\frac{1\:m}{39.37\:inches}\right)^2

\displaystyle =9.0\times 10^{-3}\:m^2          ☚