Physics for Scientists and Engineers 3E by R. Knight, P1.25

Solution:

$\displaystyle 3\:hour$

$\displaystyle =\left(3\:hour\right)\left(\frac{3600\:s}{1\:hour}\right)$

$\displaystyle =10,800\:sec$ ☚

$\displaystyle 2\:day$

$\displaystyle =\left(2\:day\right)\left(\frac{24\:hours}{1\:day}\right)\left(\frac{3600\:s}{1\:hour}\right)$

$\displaystyle =1.73\times 10^5\:sec$ ☚

$\displaystyle 1\:year$

$\displaystyle =\left(1\:year\right)\left(\frac{365.25\:days}{1\:year}\right)\left(\frac{8.64\times 10^4\:s}{1\:day}\right)$

$\displaystyle =3.16\times 10^7\:s$ ☚

$\displaystyle 215\:ft/s$

$\displaystyle =\left(215\:\frac{ft}{s}\right)\left(\frac{12\:inch}{1\:ft}\right)\left(\frac{1\:m}{39.37\:inch}\right)$

$\displaystyle =65.5\:m/s$ ☚