# Statics 1-1: Weight in Newtons of a Given Mass | Hibbeler 14th

## Solution:

The weight of an object is computed using the formula

$\displaystyle \text{Weight}=\text{mass}\times 9.81\:\text{m/s}^2$

### Part A

$\displaystyle \text{Weight}=8\:\text{kg}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=78.5\:\text{newtons}$          ◀

### Part B

$\displaystyle \text{Weight}=0.04\:\text{kg}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=0.3924\:\text{newtons}$          ◀

### Part C

$\displaystyle \text{Weight}=760\:\text{Mg}\times \frac{1000\:\text{kg}}{1\:\text{Mg}}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=7\:455\:600\:\text{newtons}$          ◀