The gusset plate is subjected to the forces of three members. Determine the tension force in member C and its angle θ for equilibrium. The forces are concurrent at point O. Take F=8 kN.
Solution:
Free-body diagram:
Equations of Equilibrium:
Taking the sum of forces in the x-direction:
\begin{aligned} T \cos \beta-\frac{4}{5}(8) & = 0 & & \\ T \cos \beta& = \frac{4}{5}(8) & &\\ T \cos \beta & = 6.4 \qquad \qquad & & (1)\\ \end{aligned}
Taking the sum of forces in the y-direction:
\begin{aligned} 9-\frac{3}{5}(8)-T \sin \beta & = 0 & &\\ T \sin \beta & =9-\frac{3}{5}(8) & & \\ T \sin \beta & =4.2 & &\qquad \qquad (2) \end{aligned}
Equation (2) divided by equation (1) to solve for angle β.
\begin{aligned} \dfrac{T \sin \beta}{T \cos \beta} & = \frac{4.2}{6.4} \\ \tan \beta & = 0.65625 \\ \beta & =\tan ^{-1}(0.65625) \\ \beta & =33.27 \degree \end{aligned}
Substitute the solved value of the angle β to equation (1) to solve for T.
\begin{aligned} T \cos \beta & =6.4 \\ T & = \dfrac{6.4}{\cos \beta}\\ T & = \dfrac{6.4}{\cos 33.27 \degree}\\ T & =7.65 \ \text{kN} \end{aligned}
Solve for the value of the unknown angle θ:
\begin{aligned} \theta & = \beta +\tan ^{-1} \left( \frac{3}{4}\right) \\ \theta & = 33.27 \degree + 36.87 \degree \\ \theta & =70.14\degree \end{aligned}
Therefore, the tension force in member C is 7.65 kN and its angle θ is 70.14°.