Category Archives: Engineering Mathematics Blog

Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 4

Advertisements
Advertisements

PROBLEM:

Express the distance D traveled in t hr by a car whose speed is 60 km/hr.

Advertisements
Advertisements

SOLUTION:

\begin{align*}
\text{Distance} & = \text{Rate} \times \text{Time} \\
D & =\left(60\:\text{km/hr} \right)\cdot t \ \text{hr} \\
D & =60t \ \text{km} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)\\
\end{align*}
Advertisements
Advertisements

Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 3

Advertisements
Advertisements

PROBLEM:

If \displaystyle y= \tan\left(x+\pi \right), find x as a function of y.

Advertisements
Advertisements

SOLUTION:

\begin{align*}
y & = \tan\left(x+\pi \right) \\
x+\pi &  = \tan^{-1}y \\
x & = \tan^{-1}y-\pi \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)\\
\end{align*}
Advertisements
Advertisements

Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1, Problem 2

Advertisements
Advertisements

PROBLEM:

If \displaystyle y=\frac{x^2+3}{x}, find x as a function of y.

Advertisements
Advertisements

SOLUTION:

\begin{align*}
y & = \frac{x^2+3}{x} \\
xy & =x^2+3 \\
x^2-xy+3&=0 
\end{align*}

Solve for x using the quadratic formula. We have a=1,\:b=-y,\:\text{and}\:c=3

\begin{align*}
x & =\frac{-b\pm \sqrt{b^2-4ac}\:}{2a} \\
x & =\frac{ -\left(-y\right)\pm \sqrt{\left(-y\right)^2-4\left(1\right)\left(3\right)}}{2\left(1\right)} \\
x & =\frac{y\pm \sqrt{y^2-12}}{2} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}
Advertisements
Advertisements

Differential and Integral Calculus by Feliciano and Uy, Exercise 1.1 Problem 1

Advertisements
Advertisements

PROBLEM:

If \displaystyle f\left(x\right)=x^2-4x, find

a) \displaystyle f\left(-5\right)

b) \displaystyle f\left(y^2+1\right)

c) \displaystyle f\left(x+\Delta x\right)

d) \displaystyle f\left(x+1\right)-f\left(x-1\right)

Advertisements
Advertisements

SOLUTION:

Part A

\begin{align*}
f\left(-5\right) & =\left(-5\right)^2-4\left(-5\right)\\
& =25+20\\
& =45 \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}

Part B

\begin{align*}
f\left(y^2+1\right) & = \left(y^2+1\right)^2-4\left(y^2+1\right)\\
& =y^4+2y^2+1-4y^2-4\\
& =y^4-2y^2-3 \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}

Part C

\begin{align*}
f\left(x+\Delta x\right)&=\left(x+\Delta x\right)^2-4\left(x+\Delta x\right)\\
& =\left(x+\Delta x\right)\left[\left(x+\Delta x\right)-4\right]\\
& =\left(x+\Delta x\right)\left(x+\Delta x-4\right) \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)\\ 
\end{align*}

Part D

\begin{align*}
f\left(x+1\right)-f\left(x-1\right) & =\left[\left(x+1\right)^2-4\left(x+1\right)\right]-\left[\left(x-1\right)^2-4\left(x-1\right)\right]\\
& = \left[x^2+2x+1-4x-4\right]-\left[x^2-2x+1-4x+4\right]\\
& =x^2-x^2+2x-4x+2x+4x+1-4-1-4\\
& =4x-8\\
& =4\left(x-2\right) \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}
Advertisements
Advertisements

College Physics by Openstax Chapter 2 Problem 31

A swan on a lake gets airborne by flapping its wings and running on top of the water.

(a) If the swan must reach a velocity of 6.00 m/s to take off and it accelerates  from rest at an average rate of  0.350 m/s2, how far will it travel before becoming airborne?

(b) How long does this take?

Solution:

Part A

We are given the following values: v_f=6.00\:\text{m/s}; v_0=0\:\text{m/s}; and a=0.350\:\text{m/s}^2.

From the kinematic equations, the most applicable formula to solve for the change in distance, \Delta \text{x}, is

\left(v_f\right)^2=\left(v_0\right)^2+2a\Delta x

Solving for \Delta \text{x} in terms of the other variables, we have

\Delta x=\frac{\left(v_f\right)^2-\left(v_0\right)^2}{2a}

Substituting the given values, 

\begin{align*}
\Delta x & =\frac{\left(v_f\right)^2-\left(v_0\right)^2}{2a} \\
\Delta x  & =\frac{\left(6.00\:\text{m/s}\right)^2-\left(0.00\:\text{m/s}\right)^2}{2\left(0.350\:\text{m/s}^2\right)} \\
\Delta x  & =51.4286\:\text{m} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}

Part B

From the formula v_f=v_0+at, solve for time, t in terms of the other variables.

t=\frac{v_f-v_0}{a}

Substitute the given values

\begin{align*}
t & =\frac{v_f-v_0}{a} \\
t & =\frac{6.00\:\text{m/s}-0.00\:\text{m/s}}{0.350\:\text{m/s}^2} \\
t & =17.1429\:\text{s} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}
Advertisements
Advertisements

College Physics by Openstax Chapter 2 Problem 30

A fireworks shell is accelerated from rest to a velocity of 65.0 m/s over a distance of 0.250 m.

(a) How long did the acceleration last?

(b) Calculate the acceleration.

Solution:

We are given the following values:v_0=0\:\text{m/s}; v_f=65.0\:\text{m/s}; and \Delta x=0.250\:\text{m}.

We can immediately solve for the acceleration using the given values, so we are going to answer Part B first.

Part B

Solve for the acceleration first using the formula

\left(v_f\right)^2=\left(v_0\right)^2+2a\Delta x

We solve for acceleration in terms of the other variables.

a=\frac{\left(v_f\right)^2-\left(v_0\right)^2}{2\Delta x}

Substitute the given values

\begin{align*}
a & =\frac{\left(v_f\right)^2-\left(v_0\right)^2}{2\Delta x} \\
a & = \frac{\left(65.0\:\text{m/s}\right)^2-\left(0\:\text{m/s}\right)^2}{2\left(0.250\:\text{m}\right)} \\
a & =8450\:\text{m/s}^2 \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}

Part A

To solve for the time of this motion, we shall use the formula

v_f=v_0+at

Solving for time, t, in terms of the other variables we have.

t=\frac{v_f-v_0}{a}

We now substitute the values given, and the computed acceleration to find the time.

\begin{align*}
t & =\frac{v_f-v_0}{a} \\
t & =\frac{65.0\:\text{m/s}-0\:\text{m/s}}{8450\:\text{m/s}^2} \\
t & =7.6922\:\times 10^{-3}\:\text{s}\ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)
\end{align*}
Advertisements
Advertisements

Home

Resources and Services

hardbound books on brown wooden table

Textbook Solutions

We provide solutions for selected textbooks. Feel free to browse them as a guide for your review for an assignment or an upcoming quiz or exam. If you need the solution manual for a specific book, kindly fill-up this form, and we will get back to you within 24 hours. Kindly indicate that you want the solution manual in the message box.

Homework or Assignment Help

Our pool of experts in Mathematics, Engineering Sciences, and Civil Engineering major courses are ready to help you for any homework or assignment you have. Kindly fill-up this form, or send us a direct email to [email protected]

pile of assorted novel books
photo of cat standing on top of a book

Live Tutorial Sessions

If you wish to learn every bit of concept of your lesson in Mathematics or Engineering Sciences, you can try our one-to-one live online tutorial session through Zoom. Our academic expert teachers are only one click away from your computer no matter where you are in the world. You can fill-up this form, or directly send an email to [email protected]

Contact Us!

Email: [email protected]

WhatsApp: +639178611702

Connect With Us!

Facebook Logo in Engineering-Math.org

Facebook

Twitter logo in Engineering-Math.org

X

Tumblr logo in Engineering-Math.org

Tumblr

Mortgage Project

You can buy the solution to this project for only $10 right here.

A home will likely be the biggest purchase a person ever makes, along with being the most intimidating purchase. But the suitable news is most of the problems homebuyers face have a quick solution, if accomplished before trying to get a mortgage.

Also the purpose of this project is help you to overcome the imitating home buying process, definitely it will gave a chance to get familiar with the process:

  • Check your credit report so you are mindful of what your current credit score is before for a loan. Credit reporting agencies must give you one free report annually.
  • Try to work closely with your banker to figure out how much you can borrow and which loan exactly fits you.
  • Acquire what current mortgage rates are. Bankers are there to help you understand how that translates into monthly mortgage payments and that’s the purpose of this project.

The following formula is used for figuring out a monthly home mortgage payment:

\displaystyle M=\frac{Lr\left[1+\frac{r}{12}\right]^{12t}}{12\left[\left(1+\frac{r}{12}\right)^{12t}-1\right]}

where:           L=the loan amount in dollars
                        r = the annual interest rate expressed as decimal
                        t = the number of years of the loan
                       M = the monthly payment in dollars

You are looking to buy a $325,000 home in Haverhill. If Bank of America will give them a 30-year mortgage at 6% annual interest rate for the cost of the house after they receive a 10% down payment.

A. Determine the loan amount?

B. How much their monthly payment will be?  

C. At the end of the 30-years, how much total money will you have paid to Bank of America for your home? In another word how much did the $325,000 house really cost the couple? 

D. How much interest will they have paid?       

E. How many of her monthly payment go toward the interest?

F. What percent increase over the cost of the home does this interest represent? 

G. Redo and re-answer all questions, but this time for 15 years?

Do analysis comparison between 30 and 15 years mortgage (at least one page not double spacing).