Notes

Solution:

The weight of an object is computed using the formula

$\displaystyle \text{Weight}=\text{mass}\times 9.81\:\text{m/s}^2$

Part A

$\displaystyle \text{Weight}=8\:\text{kg}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=78.5\:\text{newtons}$          ◀

Part B

$\displaystyle \text{Weight}=0.04\:\text{kg}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=0.3924\:\text{newtons}$          ◀

Part C

$\displaystyle \text{Weight}=760\:\text{Mg}\times \frac{1000\:\text{kg}}{1\:\text{Mg}}\times 9.81\:\text{m/s}^2$

$\displaystyle \text{Weight}=7\:455\:600\:\text{newtons}$          ◀

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Solution:

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Solution:

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We already have the answer to the problem, but we need some time to encode it. For the mean time, you can request the solution to the problem to expedite the posting of solution. Also, you can purchase the complete solution manual of College Physics by Openstax.

Solution:

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We already have the answer to the problem, but we need some time to encode it. For the mean time, you can request the solution to the problem to expedite the posting of solution. Also, you can purchase the complete solution manual of College Physics by Openstax.

Solution:

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We already have the answer to the problem, but we need some time to encode it. For the mean time, you can request the solution to the problem to expedite the posting of solution. Also, you can purchase the complete solution manual of College Physics by Openstax.