PROBLEM:
State how many significant figures are proper in the results of the following calculations:
\begin{align*} \left(a\right)\:\frac{\left(106.7\right)\left(98.2\right)}{\left(46.210\right)\left(1.01\right)} \ \qquad \ \left(b\right)\:\left(18.7\right)^2 \ \qquad \ \left(c\right)\:\left(1.60\times 10^{-19}\right)\left(3712\right) \end{align*}
SOLUTION:
Part A
The answer is limited by 98.2 and 1.01. They are both 3 significant figures. So the result should be 3 significant figures.
Part B
The answer is limited by 18.7. The answer should be 3 significant figures. So the result should be 3 significant figures.
Part C
The answer is limited by 1.60 which is 3 significant figures. So the result should be 3 significant figures.
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