Tag Archives: Engineering Mechanics: Statics 14th Edition Complete Solution Manual

Problem 1.2 – Expressing density to SI units

Wood has a density of 4.70 slug/ft3. What is its density expressed in SI units?

Solution:

\displaystyle 4.70\:\text{slug/ft}^3\times \left[\frac{\left(1\:\text{ft}^3\right)\left(14.59\:\text{kg}\right)}{\left(0.3048\:\text{m}\right)^3\:\left(1\:\text{slug}\right)}\right]=2.42\:\text{Mg/m}^3

Rounding off to 3 significant figures

Round off the following numbers to three significant figures: (a) 58 342 m, (b) 68.534 s, (c) 2553 N, and (d) 7555 kg.

Statics of Rigid Bodies 14th Edition by RC Hibbeler, Problem 1-6

Solution:

Part A

\begin{align*}
58 \ 342 \ \text{m} & = 58.342\times 10^{3} \ \text{m}\\
& = 58.342 \ \text{km}\\
& = 58.3 \ \text{km}
\end{align*}

Part B

\begin{align*}
68.534 \ \text{s} & = 68.5 \ \text{s}
\end{align*}

Part C

\begin{align*}
2553 \ \text{N} & = 2.553 \ \text{kN}\\
& = 2.55 \ \text{kN}
\end{align*}

Part D

\begin{align*}
7555 \ \text{kg} & = 7.555\times 10^3 \ \text{kg}\\
& = 7.555 \times 10^3 \times 10^3 \ \text{g}\\
& = 7.555 \times 10^6 \ \text{g} \\
& = 7.555 \ \text{Mg}\\
& = 7.56 \ \text{Mg}
\end{align*}