Engineering Mechanics: Statics 14th Edition by RC Hibbeler Solution Manual by Engineering-Math.org
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If a man weighs 155 lb on earth, specify (a) his mass in slugs, (b) his mass in kilograms, and (c) his weight in newtons. If the man is on the moon, where the acceleration due to gravity is gm=5.30 ft/s², determine (d) his weight in pounds, and (e) his mass in kilograms.
Engineering Mechanics: Statics 13th Edition by RC Hibbeler, Problem 1-21 Engineering Mechanics: Statics 14th Edition by RC Hibbeler, Problem 1-20
Solution:
Part A
From the formula, W=mg, we can solve for the mass by dividing the weight by the acceleration due to gravity. That is
m=gW=32.2ft/s2155lb=4.81slug
Part B
Convert the slug to kilograms, knowing that 1 slug = 14.59 kg.
m=(32.2155slug)(1kg14.59kg)=70.2kg
Part C
Convert the 155 lb to newtons using 1 lb = 4.448 N.
Two particles have a mass of 8 kg and 12 kg, respectively. If they are 800 mm apart, determine the force of gravity acting between them. Compare this result with the weight of each particle.
Engineering Mechanics: Statics 13th Edition by RC Hibbeler, Problem 1-20 Engineering Mechanics: Statics 14th Edition by RC Hibbeler, Problem 1-21
Using the SI system of units, show that Eq. 1–2 is a dimensionally homogeneous equation which gives F in newtons. Determine to three significant figures the gravitational force acting between two spheres that are touching each other. The mass of each sphere is 200 kg and the radius is 300 mm.
Engineering Mechanics: Statics 13th Edition by RC Hibbeler, Problem 1-18 Engineering Mechanics: Statics 14th Edition by RC Hibbeler, Problem 1-15
Solution:
To prove that F is in Newtons, we have
F=G⋅r2m1m2=(kg⋅s2m3)(m2kg⋅kg)=s2kg⋅m=N
Now, if we substitute the given values into the equation
What is the weight in newtons of an object that has a mass of: (a) 10 kg, (b) 0.5 g, and (c) 4.50 Mg? Express the result to three significant figures. Use an appropriate prefix.
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