## Analyzing Position versus Time Graphs: Conceptual Question| University Physics

Two cars travel on the parallel lanes of a two-lane road. The cars’ motions are represented by the position versus time graph shown in the figure. Answer the questions using the times from the graph indicated by letters.

## Position versus Time Graphs Conceptual Question| University Physics

The motions described in each of the questions take place at an intersection on a two-lane road with a stop sign in each direction. For each motion, select the correct position versus time graph. For all of the motions, the stop sign is at the position x=0, and east is the positive x-direction.

## Calculating Velocity from a Position-Time Graph| University Physics

The figure is the position-versus-time graph of a jogger. PART A. What is the jogger’s velocity at t = 10 s?

## Arizona State University| PHY 121: Univ Physics I: Mechanics|Homework 1-2| Velocity from Graphs of Position versus Time

An object moves along the x-axis during four separate trials. Graphs of position versus time for each trial (with the same scales on each axis) are shown in the figure.During which trial or trials is the object's velocity not constant

## Arizona State University| PHY 121: Univ Physics I: Mechanics|Homework 1-2| Average Velocity from a Position vs. Time Graph

Consulting the graph shown in the figure, find the object's average velocity over the time interval from 0 to 1 second.

## Arizona State University| PHY 121: Univ Physics I: Mechanics|Homework 1-2| Given Positions, Find Velocity and Acceleration

The table shows the x coordinate of a moving object. The position is tabulated at 1-s intervals. The x coordinate is indicated below each time. You should make the simplification that the acceleration of the object is bounded and contains no spikes.

## Arizona State University| PHY 121: Univ Physics I: Mechanics|Homework 1-1| Using Significant Figures

Your bedroom has a rectangular shape, and you want to measure its area. You use a tape that is precise to 0.001 m and find that the shortest wall in the room is 3.547 m long. The tape, however, is too short to measure the length of the second wall, so you use a second tape, which is longer but only precise to 0.01 m. You measure the second wall to be 4.79 m long. Which of the following numbers is the most precise estimate that you can obtain from your measurements for the area of your bedroom?

## College Physics Problem 1.28

A car engine moves a piston with a circular cross section of  7.500±0.002 cm diameter a distance of 3.250±0.001 cm  to compress the gas in the cylinder. (a) By what amount is the gas decreased in volume in cubic centimeters? (b) Find the uncertainty in this volume. [toggle] The average volume is Get the percent … Continue reading College Physics Problem 1.28

## College Physics Problem 1.27

The length and width of a rectangular room are measured to be 3.955 ±0.005 m and 3.050 ± 0.005 m . Calculate the area of the room and its uncertainty in square meters. [toggle] The average area of the room is Compute for the percent uncertainties of each dimension. The percent uncertainty in the area … Continue reading College Physics Problem 1.27

## College Physics Problem 1.26

When non-metric units were used in the United Kingdom, a unit of mass called the pound-mass (lbm) was employed, where 1 lbm=0.4539 kg. (a) If there is an uncertainty of 0.0001 kg in the pound-mass unit, what is its percent uncertainty? (b) Based on that percent uncertainty, what mass in pound-mass has an uncertainty of … Continue reading College Physics Problem 1.26