#### Freight trains can produce only relatively small accelerations and decelerations.

#### (a) What is the final velocity of a freight train that accelerates at a rate of 0.0500 m/s^{2} for 8.00 minutes, starting with an initial velocity of 4.00 m/s?

#### (b) If the train can slow down at a rate of 0.550 m/s^{2}, how long will it take to come to a stop from this velocity?

#### (c) How far will it travel in each case?

**Solution:**

### Part A

The final velocity can be solved using the formula . We substitute the given values.

**Part B**

Rearrange the equation we used in part (a) by solving in terms of t, we have

### Part C

The change in position for part (a), , or distance traveled is computed using the formula

For the situation in part (b), the distance traveled is computed using the formula