## College Physics Problem 2.29

Freight trains can produce only relatively small accelerations and decelerations. (a) What is the final velocity of a freight train that accelerates at a rate of $latex 0.0500\:m/s^2&s=1&fg=000000$ for 8.00 minutes, starting with an initial velocity of 4.00 m/s? (b) If the train can slow down at a rate of $latex 0.550\:m/s&s=1&fg=000000$, how long will it take to … Continue reading College Physics Problem 2.29

## College Physics Problem 2.28

A powerful motorcycle can accelerate from rest to 26.8 m/s (100 km/h) in only 3.90 s. (a) What is its average acceleration? (b) How far does it travel in that time? SOLUTION: Part (a). The average acceleration of the motorcycle can be solved using the equation $latex \overline{a}=\frac{\Delta v}{\Delta t}&s=0&fg=000000$. Substitute the given into the equation. … Continue reading College Physics Problem 2.28

## College Physics Problem 2.19

Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed and time are classified). What is its average acceleration in $latex m/s^{2}&s=1&fg=000000$ and in multiples of $latex g\:(9.80\:m/s^{2})&s=1&fg=000000$ ? SOLUTION: The formula for acceleration is  $latex a=\frac{v_f-v_0}{t}&s=1&fg=000000$ Substituting the given values $latex a=\frac{6.5\times 10^3\:m/s-0\:m/s}{60.0\:s}&s=1&fg=000000$ … Continue reading College Physics Problem 2.19

## College Physics Problem 2.18

A commuter backs her car out of her garage with an acceleration of $latex 1.40\:m/s^{2}&s=1&fg=000000$ . (a) How long does it take her to reach a speed of 2.00 m/s? (b) If she then brakes to a stop in 0.800 s, what is her deceleration? SOLUTION: a) The formula for acceleration is  $latex a=\frac{v_f-v_0}{t}&s=1&fg=000000$ If we … Continue reading College Physics Problem 2.18

## College Physics Problem 2.17

Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s! … Continue reading College Physics Problem 2.17

## College Physics Problem 2.16

A cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration? SOLUTION: The formula for acceleration is  $latex a=\frac{change\:in\:velocity}{time}=\frac{\Delta v}{time}=\frac{v_f-v_0}{t}&s=1&fg=000000$ Substituting the given values $latex a=\frac{30.0\:\frac{m}{s}-0}{7.00\:s}&s=1&fg=000000$ $latex a=4.29\:m/s^{2}&s=1&fg=000000$ You can now buy the complete solution manual for College Physics. Just complete the google form below.