Determine the resultant internal normal and shear force in the member at (a) section a–a and (b) section b–b, each of which passes through point A. The 500-lb load is applied along the centroidal axis of the member. SOLUTION: Part a The free-body diagram of section a-a is shown below. Solve for normal force at … Continue reading Problem 1-2|Stress | Mechanics of Materials| Ninth Edition| R.C. Hibbeler|

# Tag: Strength of Materials

The shaft is supported by a smooth thrust bearing at B and a journal bearing at C. Determine the resultant internal loadings acting on the cross section at E. SOLUTION: The free-body diagram is shown below. Solve for Cy by taking moment at point B $latex \sum M_B=0&s=1&fg=000000$ $latex C_y\left(8\right)+400\left(4\right)-800\left(12\right)=0&s=1&fg=000000$ Pass a cutting plane at … Continue reading Problem 1-1|Stress | Mechanics of Materials| Ninth Edition| R.C. Hibbeler|

Two solid cylindrical rods (1) and (2) are joined together at flange B and loaded, as shown in Figure P1.3/4. The diameter of rod (1) is 1.75 in. and the diameter of rod (2) is 2.50 in. Determine the normal stresses in rods (1) and (2). SOLUTION: Cut a FBD through rod (1). The FBD … Continue reading Mechanics of Materials by Timothy A. Philpot, P1.4

A stainless steel tube with an outside diameter of 60 mm and a wall thickness of 5 mm is used as a compression member. If the axial normal stress in the member must be limited to 200 MPa, determine the maximum load P that the member can support.

A 2024-T4 aluminum tube with an outside diameter of 2.50 in. will be used to support a 27-kip load. If the axial normal stress in the member must be limited to 18 ksi, determine the wall thickness required for the tube.

A stainless steel tube with an outside diameter of 60 mm and a wall thickness of 5 mm is used as a compression member. If the axial normal stress in the member must be limited to 200 MPa, determine the maximum load P that the member can support.