torque | Engineering Mathematics and Sciences

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The Second Condition for Equilibrium

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

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Stability

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

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Applications of Statics, Including Problem-Solving Strategies

Problem 17

Problem 18

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Simple Machines

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

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Forces and Torques in Muscles and Joints

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

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σ_1 is the only stress to use to find the factor of safety by the maximum normal stress theory of failure
- True
- False
A load is changing on a part from 1,000 lb to 5,000 lb, the average and range loads are
- 6,000 lb and 4,000 lb
- 5,000 lb and 1,000 lb
- 3,000 lb and 2,000 lb
- 1,000 lb and 5,000 lb
A part is loaded under service stress for 25,000 reversals, then under a higher stress for 35,000 reversals until failure. If the total life under the larger stress alone is 36,000 reversals, what is the estimated life under the service load?
- 900,000 reversals
- 37,000 reversals
- 50,000 reversals
- 60,000 reversals
Brittle materials fail in yielding
- True
- False
By applying 10,000 in.lb torque to this non-rotating shaft, the torque reactions are
- T1=5,000 in.lb; T2=5,000 in.lb
- T1=6,000 in.lb; T2=4,000 in.lb
- T1=4,000 in.lb; T2=6,000 in.lb
- None of the above
For a ductile material, the yield stress in shear is the same as it is for tension
- True
- False
For a loaded part, the state of stress is σ_x=2,000 psi, σ_y=-8000 psi, τ_xy=0. If σ_yp=45,000 psi, what is the factor of safety using the maximum normal stress theory of failure?
- 5.625
- 22.5
- 4.5
- 7.5
For a safe design in an alternating loading situation by the modified Goodman approach, two equations must be satisfied
- True
- False
For a shaft that is transmitting 145 HP while turning at 1,200 rpm, the torque is
- 760.2 in.lb
- 6722 in.lb
- 7615.5 in.lb
- 2235.3 in.lb
For a shaft under torque, the only type of deformation that will result is the rotation of the cross-sections with respect to each other
- True
- False
For a brittle material, there are two curves for the stress-strain relationship–one for the tension and the other for compression.
- True
- False
If a part fails by yielding, it will sustain permanent deformation
- True
- False
In order to apply one of the failure theories to estimate the factor of safety, we have to
- use the state of stress
- find the principal stresses
- calculate the maximum shear stress
- find the yielding stress of the material
Maximum shear theory of failure only applies to brittle materials
- True
- False
Stress concentration factors are functions of
- Load
- Geometry
- Material
- Geometry and type of loading
Stress concentration factors must be applied when we are using brittle materials
- True
- False
The principal stresses for a part are σ_1=20 MPa, σ_2=5 MPa. What is the factor of safety using the Mises Henckey theory of failure if σ_yp=100 MPa?
- 6.1
- 6.5
- 5.55
- 8.23
The shear stress on a cross-section of a shaft under torsion is linearly proportional to its radius
- True
- False
A torque applied to one end of a shaft, while the other end is keyed against rotation. The torque along the shaft will be proportional to the length
- True
- False
Ultimate stress is the same as yielding stress
- True
- False
When solving for the factor of safety in a combined steady and alternating loading situation, stress concentration factors must be applied for both average and range stresses.
- True
- False