College Physics Problem 1.10

a) The average distance between the Earth and the Sun is  10^{8} km. Calculate the average speed of the Earth in its orbit in kilometers per second. 
b) What is this is meters per second?


a) We assume that the earth revolves around the sun in a circular manner. Therefore, the distance between the earth and the sun will be the radius of its orbit.

The total distance traveled the earth in full revolution is 

d=2pi r

d=2 pi (10)^{8} km

d=pi times 2.0 times 10^{8} km

The total time of travel is

t=365.25 d times frac {24 hours}{1 day} times frac{3600 s}{ 1 hour}=3.15576 times 10^{7} sec

Therefore, the average speed is 


v=frac{pi times 2.0 times 10^{8} km }{3.15576 times 10^{7} sec}

v=19.91 km/s

Therefore, the average velocity of the earth is 19.91 km/s.


b) Convert 19.91 km/s to m/s.

v=frac{19.91 km}{s} times frac{1000 m}{1 km}

v=19910 m/s

Therefore, the velocity is 19910 m/s.