Tag Archives: Physics

Solution Guides to College Physics by Openstax Chapter 4 Banner

Chapter 4: Dynamics: Force and Newton’s Laws of Motion

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Newton’s Second Law of Motion: Concept of a System

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

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Newton’s Third Law of Motion: Symmetry in Forces

Problem 15

Problem 16

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Normal, Tension, and Other Example of Forces

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

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Problem Solving Strategies

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

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Further Applications of Newton’s Laws of Motion

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

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Further Applications of Newton’s Laws of Motion

Problem 52

Problem 53

Problem 54


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Solution Guides to College Physics by Openstax Chapter 3 Banner

Chapter 3: Two-Dimensional Kinematics

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Vector Addition and Subtraction: Graphical Methods

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Vector Addition and Subtraction: Analytical Methods

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Projectile Motion

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Addition of Velocities

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70


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Solution Guides to College Physics Chapter 2 Banner

Chapter 2: Kinematics

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Displacement

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Time, Velocity, and Speed

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Acceleration

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Motion Equations for Constant Acceleration in One Dimension

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Falling Objects

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Graphical Analysis of One-Dimensional Motion


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Solution Guide to College Physics by Openstax Chapter 1 Banner

Chapter 1: Introduction: The Nature of Science and Physics

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Physical Quantities and Units

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Accuracy, Precision, and Significant Figures

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Approximation


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Solution Guides for College Physics by Openstax Banner

College Physics by Openstax

You can browse on the itemized questions with solutions of the College Physics by Openstax below. Also, you can buy the whole Complete Solution Manual here.


College Physics Cover of Chapter 14

Chapter 14: Heat and Heat Transfer Methods

College Physics Cover of Chapter 15

Chapter 15: Thermodynamics

College Physics Cover of Chapter 16

Chapter 16: Oscillatory Motion and Waves

College Physics Cover of Chapter 17

Chapter 17: Physics of Hearing

College Physics Cover of Chapter 18

Chapter 18:
Electric Charge and Electric Field

College Physics Cover of Chapter 19

Chapter 19:
Electric Potential and Electric Field

College Physics Cover of Chapter 20

Chapter 20:
Electric Current, Resistance, and Ohm’s Law

College Physics Cover of Chapter 21

Chapter 21: Circuits and DC Instruments

College Physics Cover of Chapter 22

Chapter 22:
Magnetism

College Physics Cover of Chapter 23

Chapter 23:
Electromagnetic Induction, AC Circuits, and Electrical Technologies

College Physics Cover of Chapter 24

Chapter 24:
Electromagnetic Waves

College Physics Cover of Chapter 25

Chapter 25: Geometric Optics

College Physics Cover of Chapter 26

Chapter 26: Vision and Optical Instrument

College Physics Cover of Chapter 27

Chapter 27: Wave Optics

College Physics Cover of Chapter 28

Chapter 28: Special Relativity

College Physics Cover of Chapter 29

Chapter 29: Introduction to Quantum Physics

College Physics Cover of Chapter 30

Chapter 30: Atomic Physics

College Physics Cover of Chapter 31

Chapter 31: Radioactivity and Nuclear Physics

College Physics Cover of Chapter 32

Chapter 32: Medical Applications of Nuclear Physics

College Physics Cover of Chapter 33

Chapter 33:
Particle Physics

College Physics Cover of Chapter 34

Chapter 34: Frontiers of Physics


College Physics by Openstax Chapter 2 Problem 48


A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. How long does he have to get out of the way if the shot was released at a height of 2.20 m, and he is 1.80 m tall?


Solution:

The known values are: y_0=2.20\:\text{m}; y=1.80\:\text{m}; v_0=11.0\:\text{m/s}; and a=-9.80\:\text{m/s}^2

We are going to use the formula

 \Delta y=v_0t+\frac{1}{2}at^2

Substituting the given values:

\begin{align*}
 \Delta y & =v_0t+\frac{1}{2}at^2 \\
1.80\:\text{m}-2.20\:\text{m} & =\left(11.0\:\text{m/s}\right)t+\frac{1}{2}\left(-9.80\:\text{m/s}^2\right)t^2 \\
-0.40\:\text{m} & =\left(11.0\:\text{m/s}\right)t-\left(4.90\:\text{m/s}^2\right)t^2 \\
4.90t^2-11t-0.40 & =0
\end{align*}

Using the quadratic formula solve for t, we have

\begin{align*}
t & =\frac{-\left(-11\right)\pm \sqrt{\left(-11\right)^2-4\left(4.90\right)\left(-0.40\right)}}{2\left(4.90\right)} \\
\end{align*}
 t=2.28\:\text{sec}\:\:\:\:\:\text{or}\:\:\:\:\:\:t=-0.04 \ \text{sec}

We can discard the negative time, so

t=2.28\:\text{s} \ \qquad \ \color{DarkOrange} \left( \text{Answer} \right)

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